program read_TMIsst
c
c	Peter M. Woiceshyn	Aug 26, 2002
c       818-354-1450
c	Peter.M.Woiceshyn@jpl.nasa.gov
c
c   Sample program provides read statements to read in TMI sea
c          surface temperature (degrees Centigrade) data.
c
c   The TMI sst  data are on a 1440 X 320 element grid with the origin at
c      -39.875 South latitude and 0.125 degrees East longitude (i.e.,
C      a 0.25 by 0.25 degree lat/lon grid resolution ranging from
C      -39.875 (S) to 39.875 (N) in latitude & from 0.125 to 359.875
C      in East longitude).
c    
c   Two arrays exist in the file.  The first array, 'sst', contains the
c     the temperature values.  The second array, 'num', contains the
c     number of data values that were used to compute the mean
c     temperature value at a particular grid point.  A 'num' value
C     equal to 0 (zero) indicates that there were NO temperature values
C     for that grid point (over the ocean -- and obviously not over land).
C     The 'num' array values greater than zero can therefore be used to
C     identify legitimate values of SST for each grid point.
c
c   There are 12 months of data for year 2001.
c
c  Declarations:

	REAL lon(1440), lat(320)
C	
	REAL del_deg, sst(1440,320), num(1440,320)
C
	INTEGER*2    lon2, lat2
C	
	CHARACTER*3  c_mon(12)
	CHARACTER*2  yc, mc(12)
	CHARACTER*15 f_in
	CHARACTER*5  f_label
	CHARACTER*4  suff, f_ycmc

C----------------------------------------------------------------------C

	DATA   c_mon/'Jan','Feb','Mar','Apr','May','Jun',
     &	              'Jul','Aug','Sep','Oct','Nov','Dec'/

	DATA  mc/'01','02','03','04','05','06',
     &	         '07','08','09','10','11','12'/


C----------------------------------------------------------------------C

	     yc = '01'
	
	   suff = '.dat'

        f_label = c_mon(1)//yc	! Jan 2001
         f_ycmc = yc//mc(1)
  
           f_in = 'SstNite'//f_ycmc//suff
	   PRINT *,' ' 
	   PRINT *,'    '//f_in//'    '//f_label

C----------------------------------------------------------------------C

	     lon2 = 1440
	     lat2 =  320
  
	  del_deg = 0.25
  
	   PRINT *,' ' 
	   PRINT *,'    longitude array dimension =  ',lon2
	   PRINT *,'     latitude array dimension =  ',lat2
	   PRINT *,'            delta lat/lon deg = ',del_deg
	   PRINT *,' ' 

C  Construct lat & lon arrays

	DO jj = 0, lat2 - 1
	
                   lat(jj+1) = jj*del_deg - 40.0 + del_deg/2.0
	ENDdo

	DO ii = 0, lon2 - 1
	
                   lon(ii+1) = ii*del_deg + del_deg/2.0
	ENDdo
  
c
c
c	Lat range:	-39.875(S) to  39.875(N) degrees 
c
c	Lon range:	0.125(E) to 359.875(E) degrees 
c
c
	   PRINT *,' ' 
	   PRINT *,'    Reading file: ',f_in
	   PRINT *,' ' 

	       OPEN(22,file=f_in,form='unformatted')

                           print *, '    Read array sst'
		      read(22) sst

                           print *, '    Read array num'
                           print *, ' '
		      read(22) num
	
	       CLOSE(22)

	DO j = 160, 161
	     DO i = 1, 5

	  WRITE (6,'(2x,A4,I3,2x,A4,I4,2x,A6,F7.3,2X,A6,F7.3,2X,
     &               A6,F8.2,2x,A6,F6.1)') 
     &       'i = ', i,'j = ', j,
     &       ' lat = ', lat(j),' lon = ', lon(i),
     &          ' sst = ',sst(i,j), ' num = ',num(i,j)
	       
	     ENDDO
	        WRITE (6,'(A2)') ' ' 
	ENDDO
	        WRITE (6,'(A2)') ' ' 
C----------------------------------------------------------------------C
	       
	STOP

	END

C----------------------------------------------------------------------C
C
C  Output from executing this FORTRAN 77 program:
C
C host{pw}432> read_TMIsst.x
C  
C     SstNite0001.dat    Jan01
C  
C     longitude array dimension =    1440
C      latitude array dimension =    320
C             delta lat/lon deg =    0.250000
C  
C  
C     Reading file: SstNite0101.dat
C  
C     Read array sst
C     Read array num
C  
C  i = 1  j = 160   lat = -0.125   lon = 0.125   sst = 27.77   num = 16.0
C  i = 2  j = 160   lat = -0.125   lon = 0.375   sst = 27.55   num = 17.0
C  i = 3  j = 160   lat = -0.125   lon = 0.625   sst = 27.44   num = 16.0
C  i = 4  j = 160   lat = -0.125   lon = 0.875   sst = 27.34   num = 16.0
C  i = 5  j = 160   lat = -0.125   lon = 1.125   sst = 27.44   num = 16.0
C  
C  i = 1  j = 161   lat =  0.125   lon = 0.125   sst = 27.87   num = 17.0
C  i = 2  j = 161   lat =  0.125   lon = 0.375   sst = 28.04   num = 17.0
C  i = 3  j = 161   lat =  0.125   lon = 0.625   sst = 27.66   num = 15.0
C  i = 4  j = 161   lat =  0.125   lon = 0.875   sst = 27.69   num = 16.0
C  i = 5  j = 161   lat =  0.125   lon = 1.125   sst = 27.80   num = 15.0
C  
C  
C host{99pw}433> 
C
C----------------------------------------------------------------------C